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On my Ajax query the line

$filename = $_FILES['file']['name'];
echo "FILENAME : ". $filename;

Actually returns the correct filename.

So instead of tryin XMLHttpRequest (that I have not managed to get working), could I just use command like:

$handle->file_dst_name_body = 'test';

Which the upload class seems to ignore.Reply

Please read the documentation. What you are looking for is probably file_new_name_bodyReply

Thank you - it works. Just as reference to other users, the core content of my ajax_upload_image.php is as follows. This responds to the AJAX query from the above code. The AJAX code passes the tmp-file name that the Upload class uses to upload the image, and the actual file name.

I'm then using PHP to format the image file name (remove .extension). And then $handle->file_new_name_body = $orig_file; command to set the file name for the saved image.

As Colin said there is probably XMLhttpRequest method to pass the information automatically but I could not get it working. But the AJAX way works now.

// Destination directory for images
$dir_dest = '../product/images/';

$orig_file = $_FILES['file']['name'];
$file_array= explode(".", $orig_file);
$orig_file = $file_array[0];

$filename = $_FILES['file']['tmp_name'];
$dir_pics = (isset($_GET['pics']) ? $_GET['pics'] : $dir_dest);

// ---------- IMAGE UPLOAD ----------

// we create an instance of the class, giving as argument the PHP object
// corresponding to the file field from the form
// All the uploads are accessible from the PHP object $_FILES
$handle = new Upload($filename);
$return_arr = array();

// then we check if the file has been uploaded properly
// in its *temporary* location in the server (often, it is /tmp)
if ($handle->uploaded) {

    // yes, the file is on the server
    // below are some example settings which can be used if the uploaded file is an image.
    $handle->image_convert         = 'jpg';
    $handle->image_resize            = true;
    $handle->image_ratio_fill      	 = true;
    $handle->image_x                 = 64;
    $handle->image_y                 = 64;
    $handle->file_new_name_body      = $orig_file;

    // now, we start the upload 'process'. That is, to copy the uploaded file
    // from its temporary location to the wanted location
    // It could be something like $handle->Process('/home/www/my_uploads/');
    $handle->Process($dir_dest);

    // we check if everything went OK
    if ($handle->processed) {
        // everything was fine !
        echo 'File uploaded with success and formatted to 64x64 pixels (Small Image)';
        echo '<img src="'.$dir_pics.'/' . $handle->file_dst_name . '" />';
        $info = getimagesize($handle->file_dst_pathname);
        echo '  File: <a href="'.$dir_pics.'/' . $handle->file_dst_name . '">' . $handle->file_dst_name . '
';
        echo '   (' . $info['mime'] . ' - ' . $info[0] . ' x ' . $info[1] .' -  ' . round(filesize($handle->file_dst_pathname)/256)/4 . 'KB)';
    } else {
        // one error occured
        echo 'File not uploaded to the wanted location';
        echo 'Error: ' . $handle->error;
    }

// we delete the temporary files
    $handle-> Clean();

} else {
    // if we're here, the upload file failed for some reasons
    // i.e. the server didn't receive the file
    echo 'File not uploaded on the server';
    echo 'Error: ' . $handle->error;
}

if (isset($handle)) {
  echo($handle->log);
}
Reply